How many millilitres of 0.152 mol L^-1 $\mathrm { HClO } _ { 4 }$ solution are needed to neutralize 50.00 mL of 0.0793 mol L^-1 NaOH?

Question

Quizplus · Accepted Answer

To neutralize NaOH with HClO4, use the formula: $C_1V_1 = C_2V_2$. Here, $C_1 = 0.0793 \, \text{mol/L}$, $V_1 = 50.00 \, \text{mL}$, $C_2 = 0.152 \, \text{mol/L}$. Solving for $V_2$, $V_2 = \frac{C_1V_1}{C_2} = \frac{0.0793 \times 50.00}{0.152} = 26.1 \, \text{mL}$.

How Many Millilitres of 0 HClO4\mathrm { HClO } _ { 4 }HClO4​

How Many Millilitres of 0 $\mathrm { HClO } _ { 4 }$