Lithium and nitrogen react to produce lithium nitride:
6Li(s)+ $\mathrm { N } _ { 2 }$ (g)? $2 \mathrm { Li } _ { 3 }$ N(s)
How many moles of lithium nitride are produced when 0.450 mol of lithium react in this fashion?

Question

Lithium and nitrogen react to produce lithium nitride: 
6Li(s)+ $\mathrm { N } _ { 2 }$ (g)? $2 \mathrm { Li } _ { 3 }$ N(s)
How many moles of lithium nitride are produced when 0.450 mol of lithium react in this fashion?

Quizplus · Accepted Answer

The balanced equation shows that 6 moles of lithium produce 2 moles of lithium nitride. Therefore, 0.450 moles of lithium will produce (0.450 mol Li) * (2 mol Li3N / 6 mol Li) = 0.150 mol of lithium nitride.

Lithium and Nitrogen React to Produce Lithium Nitride: 6Li(s) N2\mathrm { N } _ { 2 }N2​

Lithium and Nitrogen React to Produce Lithium Nitride:
6Li(s) $\mathrm { N } _ { 2 }$