Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li(s)+ $\mathrm { N } _ { 2 }$ (g)? $2 \mathrm { Li } _ { 3 }$ N(s)
In a particular experiment,5.50 g samples of each reagent are reacted.What is the theoretical yield of lithium nitride?

Question

Quizplus · Accepted Answer

The theoretical yield is calculated based on the limiting reagent. First, calculate moles of each reactant: Li: 5.50 g / 6.94 g/mol = 0.792 mol; N2: 5.50 g / 28.02 g/mol = 0.196 mol. The reaction requires 6 moles of Li for every 1 mole of N2, so Li is the limiting reagent. The moles of Li3N produced is 0.792 mol Li / 6 = 0.132 mol Li3N. The mass of Li3N is 0.132 mol * 34.83 g/mol = 4.60 g.

Lithium and Nitrogen React in a Combination Reaction to Produce N2\mathrm { N } _ { 2 }N2​

Lithium and Nitrogen React in a Combination Reaction to Produce $\mathrm { N } _ { 2 }$