How many grams of AgNO₃ are needed to make 250. mL of a solution that is 0. 135 mol L^-1?

Question

Quizplus · Accepted Answer

To solve this problem, we need to use the formula: moles = concentration x volume First, we need to calculate the number of moles of L^-1 in the solution: moles = concentration x volume moles = 0.135 mol L-1 x 0.250 L moles = 0.03375 mol Next, we need to calculate the number of moles of AgNO₃ needed to provide 0.03375 mol of L^-1. To do this, we need to use the balanced chemical equation: 2 AgNO3 + Na2S -> Ag2S + 2 NaNO3 From the equation, we can see that the mole ratio of AgNO3 to L^-1 is 2:1. This means that we need half as many moles of AgNO3 as L^-1. moles AgNO3 = 0.5 x moles L^-1 moles AgNO3 = 0.5 x 0.03375 mol moles AgNO3 = 0.01688 mol Finally, we need to calculate the mass of AgNO₃ needed: mass = moles x molar mass mass = 0.01688 mol x 169.87 g mol-1 mass = 2.87 g Therefore, the answer is C) 5.73 g.

How Many Grams of AgNO3 Are Needed to Make 250

How Many Grams of AgNO₃ Are Needed to Make 250