Determine the density of O₃ gas at 341 K and 2.14 bar. A)3.62 g $\mathrm { L } ^ { - 1 }$ B)2.91 g $\mathrm { L } ^ { - 1 }$ C)0.321 g $\mathrm { L } ^ { - 1 }$ D)4.82 g $\mathrm { L } ^ { - 1 }$ E)3.17 g $\mathrm { L } ^ { - 1 }$

Question

Quizplus · Accepted Answer

The density of a gas can be calculated using the ideal gas equation:$$PV = nRT$$where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.We can rearrange this equation to solve for the density (mass/volume):$$ho = \frac{m}{V} = \frac{PM}{RT}$$where m is the mass and M is the molar mass.For O3, the molar mass is 48 g/mol. Plugging in the given values, we get:$$ho = \frac{(2.14 	ext{ bar})(48 	ext{ g/mol})}{(0.0821 	ext{ L atm/mol K})(341 	ext{ K})} = 3.62 	ext{ g/L}$$Therefore, the correct answer is A) 3.62 g L^-1.

Determine the Density of O3 Gas at 341 K and 2.14

Determine the Density of O₃ Gas at 341 K and 2.14