A fixed amount of gas at 25.0 °C occupies a volume of 20.0 L when the pressure is 0.8386 bar.Use Charles's law to calculate the volume (L)the gas will occupy when the temperature is increased to $131 ^ { \circ } \mathrm { C }$ while maintaining the pressure at 0.8386 bar.

Question

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Charles's Law states that $ V_1/T_1 = V_2/T_2 $. Convert temperatures to Kelvin: $ T_1 = 25 + 273.15 = 298.15 \, K $ and $ T_2 = 131 + 273.15 = 404.15 \, K $. Solve for $ V_2 $: $ V_2 = V_1 \times (T_2/T_1) = 20.0 \, L \times (404.15/298.15) \approx 27.1 \, L $.

A Fixed Amount of Gas at 25 131∘C131 ^ { \circ } \mathrm { C }131∘C

A Fixed Amount of Gas at 25 $131 ^ { \circ } \mathrm { C }$