How much energy is required to decompose 765 g of PCl₃ according to the reaction below? The molar mass of PCl₃ is 137.32 g $\mathrm { mol } ^ { - 1 }$ and may be useful. 4PCl₃(g) ? P₄(s) + 6Cl₂(g)
D_rH°= +1207 kJ

Question

How much energy is required to decompose 765 g of PCl₃ according to the reaction below? The molar mass of PCl₃ is 137.32 g

\mathrm { mol } ^ { - 1 }

and may be useful. 4PCl₃(g) ? P₄(s) + 6Cl₂(g)
D_rH°= +1207 kJ

Quizplus · Accepted Answer

First, calculate the moles of PCl₃: 765 g / 137.32 g/mol = 5.57 mol. The reaction decomposes 4 moles of PCl₃ with ΔH° = +1207 kJ. Therefore, for 5.57 moles, the energy required is (5.57 mol / 4 mol) × 1207 kJ = 1.68 × 10³ kJ.

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