Use the _DfH° Information Provided to Calculate _DrH° for the Following

Use the _DfH° information provided to calculate _DrH° for the following: $$\begin{array} { l r r l } & \mathrm { D } _ { \mathrm { f } } H ^ { \circ } ( \mathrm { kJ } \mathrm { mol } - 1 ) & \mathrm { SO } _ { 2 } \mathrm { Cl } _ { 2 } ( g ) + 2 \mathrm { H } _ { 2 } \mathrm { O } ( l ) \rightarrow 2 \mathrm { HCl } ( g ) + \mathrm { H } _ { 2 } \mathrm { SO } ( l ) \quad \mathrm { D } _ { \mathrm { r } } H ^ { \circ } = ? \\\mathrm { SO } _ { 2 } \mathrm { Cl } _ { 2 } ( g ) & - 364 & & \\\mathrm { H } _ { 2 } \mathrm { O } ( l ) & - 286 & \\\mathrm { HCl } ( g ) & 92 & \\\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } ( l ) & - 814 &\end{array}$$

A) -256 kJ mol^-1
B) +161 kJ mol^-1
C) -62 kJ mol^-1
D) +800.kJ mol^-1
E) -422 kJ mol^-1