The specific heat of copper is 0.385 J $g ^ { - 1 }$ $\mathrm { K } ^ { - 1 }$ .If 34.2 g of copper,initially at 21.0 °C,absorbs 4.689 kJ,what will be the final temperature of the copper?

Question

Quizplus · Accepted Answer

The heat absorbed (q) is calculated using the formula q = mcΔT, where m is mass, c is specific heat, and ΔT is the change in temperature. Rearranging for ΔT gives ΔT = q / (mc). Substituting the given values: ΔT = 4689 J / (34.2 g * 0.385 J/g°C) = 356°C. Adding the initial temperature (21°C) gives a final temperature of 377°C.

The Specific Heat of Copper Is 0 g−1g ^ { - 1 }g−1

The Specific Heat of Copper Is 0 $g ^ { - 1 }$