Use the data given below to construct a Born-Haber cycle to determine the lattice energy of CaO. $$\begin{array} { l r }
& \Delta H ^ { \circ } \left( \mathrm { kJ } \mathrm { mol } ^ { - } 1 \right)\
\mathrm { Ca } ( s ) \rightarrow \mathrm { Ca } ( g ) & 193 \
\mathrm { Ca } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } &590 \
\mathrm { Ca } ^ { + } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } &1010 \
2 \mathrm { O } ( g ) \rightarrow \mathrm { O } _ { 2 } ( g ) & - 498 \
\mathrm { O } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { - } ( g ) & - 141 \
\mathrm { O } ^ { - } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { 2 - } ( g ) & 878 \
\mathrm { Ca } ( s ) + \frac { 1 } { 2 } \mathrm { O } 2 ( g ) \rightarrow \mathrm { CaO } ( s ) & - 635
\end{array}$$

Question

Use the data given below to construct a Born-Haber cycle to determine the lattice energy of CaO. $$\begin{array} { l r }
& \Delta H ^ { \circ } \left( \mathrm { kJ } \mathrm { mol } ^ { - } 1 \right)\ 
\mathrm { Ca } ( s ) \rightarrow \mathrm { Ca } ( g ) & 193 \
\mathrm { Ca } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } &590 \
\mathrm { Ca } ^ { + } ( g ) \rightarrow \mathrm { Ca } ^ { + } ( g ) + \mathrm { e } ^ { - } &1010  \
2 \mathrm { O } ( g ) \rightarrow \mathrm { O } _ { 2 } ( g ) & - 498 \
\mathrm { O } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { - } ( g ) & - 141 \
\mathrm { O } ^ { - } ( g ) + \mathrm { e } ^ { - } \rightarrow \mathrm { O } ^ { 2 - } ( g ) & 878 \
\mathrm { Ca } ( s ) + \frac { 1 } { 2 } \mathrm { O } 2 ( g ) \rightarrow \mathrm { CaO } ( s ) & - 635
\end{array}$$

Quizplus · Accepted Answer

The lattice energy of CaO can be calculated using the Born-Haber cycle:```Ca(s) → Ca(g) ΔH = 193 kJ/molCa(g) → Ca+(g) + e- ΔH = 590 kJ/molCa+(g) → Ca2+(g) + e- ΔH = 1010 kJ/mol1/2 O2(g) → O(g) ΔH = 249 kJ/molO(g) + e- → O-(g) ΔH = -141 kJ/molO-(g) + e- → O2-(g) ΔH = 878 kJ/molCa2+(g) + O2-(g) → CaO(s) ΔH = -635 kJ/mol```The lattice energy of CaO is the sum of the enthalpy changes for the following reactions:```Ca(s) → Ca(g)Ca(g) → Ca+(g) + e-Ca+(g) → Ca2+(g) + e-1/2 O2(g) → O(g)O(g) + e- → O-(g)O-(g) + e- → O2-(g)Ca2+(g) + O2-(g) → CaO(s)```The lattice energy of CaO is -3414 kJ/mol.

Use the Data Given Below to Construct a Born-Haber Cycle