Consider the following reaction at equilibrium. What effect will reducing the pressure of the reaction mixture have on the system? Xe(g) + 2F₂(g) ⇌ XeF₄(g)

Question

Quizplus · Accepted Answer

Reducing the pressure of the reaction mixture will cause the equilibrium to shift towards the side with more moles of gas to counteract the change. In this reaction, the reactants side has 3 moles of gas (1 Xe + 2 F2) compared to 1 mole of gas on the products side (XeF4), so the reaction will shift towards the reactants.

Consider the Following Reaction at Equilibrium