Determine the [OH^-] concentration in a 0.169 mol L^-1 Ca(OH)₂ solution. A)0.338 mol L^-1 B)0.169 mol L^-1 C)5.92 × 10^-14 mol L^-1 D)2.96 × 10^-14 mol L^-1 E)0.298 mol L^-1

Question

Quizplus · Accepted Answer

Calcium hydroxide, Ca(OH)₂, dissociates into one Ca²⁺ ion and two OH⁻ ions. Therefore, the concentration of OH⁻ ions is twice the concentration of Ca(OH)₂, which is 2 × 0.169 mol L⁻¹ = 0.338 mol L⁻¹.

Determine the [OH-] Concentration in a 0

Determine the [OH^-] Concentration in a 0