How many millilitres of 0.120 mol L^-1 NaOH are required to titrate 50.0 mL of 0.0998 mol L^-1 acetic acid to the equivalence point? Acetic acid is monoprotic.The $K _ { a }$ of acetic acid is 1.8 × 10^-5. A)41.6 B)60.1 C)50.0 D)1.77 E)2.82

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Quizplus · Accepted Answer

To find the volume of NaOH needed, use the formula: $C_1V_1 = C_2V_2$. Here, $C_1 = 0.0998 \, \text{mol/L}$, $V_1 = 50.0 \, \text{mL}$, and $C_2 = 0.120 \, \text{mol/L}$. Solving for $V_2$, we get $V_2 = \frac{C_1V_1}{C_2} = \frac{0.0998 \times 50.0}{0.120} = 41.6 \, \text{mL}$.

How Many Millilitres of 0 KaK _ { a }Ka​ Of Acetic Acid Is 1

How Many Millilitres of 0 $K _ { a }$ Of Acetic Acid Is 1