Consider the following reaction at constant pressure. Use the information here to determine the value of ΔSsurr at 398 K. Predict whether or not this reaction will be spontaneous at this temperature. 4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(g) ΔrH = -1267 kJ
A) ΔSsurr = +12.67 kJ K-1 mol-1, reaction is not spontaneous
B) ΔSsurr = -12.67 kJ K-1 mol-1, reaction is spontaneous
C) ΔSsurr = +50.4 kJ K-1 mol-1, reaction is not spontaneous
D) ΔSsurr = +3.18 kJ K-1 mol-1, reaction is spontaneous
E) ΔSsurr = -3.18 kJ K-1 mol-1, reaction is not spontaneous
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