Determine Δ_rG° at 298 K using the following information:
$\quad$ CaCO₃(s) → CaO(s) + CO₂(g) $\quad$ Δ_rH°= +179.2 kJ mol^-1; $\quad$ Δ_rS°= +160.2 J K^-1 mol^-1

Question

Determine Δ_rG° at 298 K using the following information: $\quad$CaCO₃(s)→ CaO(s)+ CO₂(g)$\quad$Δ_rH°= +179.2 kJ mol^-1; $\quad$Δ_rS°= +160.2 J K^-1 mol^-1

Quizplus · Accepted Answer

Δ_rG°= Δ_rH° - TΔ_rS° We are given: Δ_rH°= +179.2 kJ mol^-1 Δ_rS° = +160.2 J K^-1 mol^-1 T= 298 K We need to convert Δ_rS° from J K-1 mol-1 to kJ K-1 mol-1 Δ_rS°= 160.2 J K-1 mol-1 / 1000 = 0.1602 kJ K-1 mol-1 Now we can calculate: Δ_rG°= +179.2 kJ mol^-1 - (298 K x 0.1602 kJ K-1 mol-1) Δ_rG°= 131.5 kJ mol^-1 Therefore, the best choice is D, which is +131.5 kJ mol^-1.

Determine ΔrG° at 298 K Using the Following Information \quad CaCO3(s)→ CaO(s)+ CO2(g)

Determine Δ_rG° at 298 K Using the Following Information $\quad$ CaCO₃(s)→ CaO(s)+ CO₂(g)