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Write a Nuclear Equation for the Alpha Decay Of 92238{ } _ { 92 } ^ { 238 }

Question 6

Multiple Choice

Write a nuclear equation for the alpha decay of 92238{ } _ { 92 } ^ { 238 } U.


A) 92238U01n+92237U{ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { 0 } ^ { 1 } \mathrm { n } + { } _ { 92 } ^ { 237 } \mathrm { U }
B) 92238U10e+93238 Np{ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { - 1 } ^ { 0 } \mathrm { e } + { } _ { 93 } ^ { 238 } \mathrm {~Np}
C) 92238U24He+90234Th{ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { 2 } ^ { 4 } \mathrm { He } + { } _ { 90 } ^ { 234 } \mathrm { Th }
D) 92238U+10e+91238 Pa{ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { + 1 } ^ { 0 } \mathrm { e } + { } _ { 91 } ^ { 238 } \mathrm {~Pa}
E) 92238U10e+91238 Pa{ } _ { 92 } ^ { 238 } \mathrm { U } \rightarrow { } _ { - 1 } ^ { 0 } \mathrm { e } + { } _ { 91 } ^ { 238 } \mathrm {~Pa}

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