Determine the identity of the daughter nuclide from the positron emission of $ { }_{8}^{15} \mathrm{O} $

Question

Quizplus · Accepted Answer

In positron emission, a proton is converted into a neutron and a positron is emitted. This means that the atomic number decreases by one, while the atomic mass remains the same. In this case, the original nuclide is oxygen-15, which has an atomic number of 8. After emitting a positron, the atomic number decreases to 7, which corresponds to nitrogen. Thus, the daughter nuclide is $^{15}_{7}\mathrm{N}$, and the correct answer is C.

Determine the Identity of the Daughter Nuclide from the Positron 815O { }_{8}^{15} \mathrm{O} 815​O

Determine the Identity of the Daughter Nuclide from the Positron ${ }_{8}^{15} \mathrm{O}$