Suppose an actual census showed that 18.4% of the households in California have incomes in excess of $50,000.The probability that the sample proportion will be 0.22 or greater for a random sample of 750 households is:
A) 0.0055.
B) 0.9945.
C) 0.9949.
D) 0.0041.
E) not enough information given for estimation.

Question

Quizplus · Accepted Answer

The sample proportion follows a normal distribution with mean 0.184 and standard deviation sqrt((0.184)(0.816)/750). Using the z-score formula, the probability of the sample proportion being 0.22 or greater is approximately 0.0055.

Suppose an Actual Census Showed That 18