A 6-sided die has been weighted so that 5 or 6 comes up 3 times as often as 1 or 2.Also,3 or 4 comes up 2 times as often as 1 or 2.Player A wins $6 if 1 comes up,$5 if 2 comes up and $4 if 3 comes up.Player B wins $3 if 4 comes up,$2 if 5 comes up and $1 if 6 comes up.What is the value of E[A] - E[B],where E[A] is the expectation of winning for player A and E[B] is the expectation of winning for player B?
A)0.33
B)0.67
C)-0.67
D)-0.33

Question

Quizplus · Accepted Answer

The expected value for player A is (1/6 * 6) + (1/6 * 5) + (1/6 * 4) = 5.The expected value for player B is (1/6 * 3) + (1/6 * 2) + (1/6 * 1) = 2.Therefore, E[A] - E[B] = 5 - 2 = 3.

A 6-Sided Die Has Been Weighted So That 5 or 6