Instruction 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tailed test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Instruction 9-6,if the test is performed with a level of significance of 0.10,the engineer can conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650.

Question

Quizplus · Accepted Answer

Since the p-value (0.080) is greater than the chosen level of significance (0.10), we fail to reject the null hypothesis. Therefore, we cannot conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650.

Instruction 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested