Instruction 13 ANOVA Note: Adj R Square = Adjusted R Square; Std

Instruction 13.23
The Head of the Accounting Department wanted to see if she could predict the average grade of students using the number of course units (credits) and total university entrance exam scores of each. She takes a sample of students and generates the following Microsoft Excel output:
OUTPUT
SUMMARY
$\begin{array} { l l } \text { Regression Statistics } & \\ \text { MultipleR } & 0.916 \\ \text { R Square } & 0.839 \\ \text { Adj. R Square } & 0.732 \\ \text { Std. Error } & 0.24685 \\ \text { Observations } & 6 \end{array}$

ANOVA
$\begin{array} { l l l l l l } & d f & \text { SS } & \text { MS } & F & \text { Signiff } \\ \text { Regression } & 2 & 0.95219 & 0.47610 & 7.813 & 0.0646 \\ \text { Residual } & 3 & 0.18281 & 0.06094 & & \\ \text { Total } & 5 & 1.13500 & & & \\ & & & & & \\ & \text { Coeff } & \text { StdError } & t \text { Stat } & p \text { value } & \\ \text { Intercept } & 4.593897 & 1.13374542 & 4.052 & 0.0271 & \\ \text { GDP } & - 0.247270 & 0.06268485 & - 3.945 & 0.0290 & \\ \text { Price } & 0.001443 & 0.00101241 & 1.425 & 0.2494 & \end{array}$ Note: Adj. R Square = Adjusted R Square; Std. Error = Standard Error
-Referring to Instruction 13.23,the Head of Department wants to test H₀: ?₁ = ?₂ = 0.At a level of significance of 0.05,the null hypothesis is rejected.