A shear force of 400 N is applied to one face of an aluminum cube with sides of 30 cm while the opposite face is held fixed in place.What is the resulting displacement of the face? (The shear modulus for aluminum is 2.5 × 10¹⁰ N/m²) A) 1.9 × 10^-8 m B) 2.6 × 10^-8 m C) 4.4 × 10^-8 m D) 5.3 × 10^-8 m E) 8.2 × 10^-8 m

Question

Quizplus · Accepted Answer

The displacement can be calculated using the formula for shear strain: displacement = (force × side length) / (shear modulus × area). Substituting the given values, the displacement is 5.3 × 10^-8 m.

A Shear Force of 400 N Is Applied to One