When a fixed amount of ideal gas goes through an isochoric process,
A) its internal (thermal) energy does not change.
B) the gas does no work.
C) no heat enters or leaves the gas.
D) its temperature must increase.
E) its pressure must increase.

Question

Quizplus · Accepted Answer

In an isochoric process, the volume of the gas remains constant. Since work done by a gas is given by W = PΔV (where P is pressure and ΔV is the change in volume), if the volume does not change (ΔV = 0), no work is done by the gas. Choices A, C, D, and E are not necessarily true for an isochoric process, as changes in internal energy, heat exchange, and temperature or pressure depend on specific conditions and energy transfers, not solely on the process being isochoric.

When a Fixed Amount of Ideal Gas Goes Through an Isochoric