A compression,at a constant pressure of 190 kPa,is performed on 5.0 moles of an ideal monatomic gas.The compression reduces the volume of the gas from to The ideal gas constant is R = 8.314 J/mol • K.The work done by the gas is closest to

Question

Quizplus · Accepted Answer

First, we need to calculate the initial and final volumes in m³:

$V_1 = 11.83	imes 10^{-6}	ext{ m}^3$

$V_2 = 11.73	imes 10^{-6}	ext{ m}^3$

Now we can use the formula for the work done by a gas at constant pressure:

$W = -P\Delta V = -P(V_2 - V_1)$

Substituting the values:

$W = -(190	ext{ kPa})((11.73 - 11.83)	imes 10^{-6}	ext{ m}^3)$

$W \approx -13	ext{ kJ}$

Note: The negative sign of the work indicates that the gas is doing work on its surroundings, which is consistent with the fact that it is being compressed.

A Compression,at a Constant Pressure of 190 KPa,is Performed on 5.0