A proton is placed in an electric field of intensity 700 N/C.What are the magnitude and direction of the acceleration of this proton due to this field? (mproton = 1.67 × 10-27 kg, 
A) 6.71 ×
m/
opposite to the electric field
B) 6.71 ×
m/
opposite to the electric field
C) 6.71 ×
m/
in the direction of the electric field
D) 67.1 ×
m/
opposite to the electric field
E) 67.1 ×
m/
in the direction of the electric field
Correct Answer:
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