A very small object carrying -6.0 μC of charge is attracted to a large,well-anchored,positively charged object.How much kinetic energy does the negatively charged object gain if the potential difference through which it moves is 3.0 mV?
A) 18 nJ
B) 0.50 kJ
C) 0.50 J
D) 6.0 μJ

Question

A very small object carrying -6.0 μC of charge is attracted to a large,well-anchored,positively charged object.How much kinetic energy does the negatively charged object gain if the potential difference through which it moves is 3.0 mV? 
A) 18 nJ 
B) 0.50 kJ 
C) 0.50 J 
D) 6.0 μJ

Quizplus · Accepted Answer

The formula for calculating the kinetic energy gained by a charged particle moving through a potential difference is given by:
K = qV
where K is the kinetic energy, q is the charge of the particle, and V is the potential difference. 
Substituting the given values, we get:
K = (-6.0 μC)(3.0 mV)
K = -18 μJ
Note that the negative sign indicates that the kinetic energy gained is negative, which means that the particle loses kinetic energy. However, the question asks for the magnitude of the kinetic energy gained, which is given by the absolute value of -18 μJ, which is 18 μJ, or 18 nJ in SI units. Therefore, the best choice is A.

A Very Small Object Carrying -6