A circular loop of wire of radius 10 cm carries a current of 6.0 A.What is the magnitude of the magnetic field at the center of the loop? (μ₀ = 4π × 10^-7 T • m/A) A) 3.8 × 10^-5 T B) 3.8 × 10^-7 T C) 1.2 × 10^-5 T D) 1.2 × 10^-7 T E) 3.8 × 10^-8 T

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Quizplus · Accepted Answer

The magnetic field at the center of a circular loop is given by the formula $B = \frac{\mu_0 I}{2r}$, where $\mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A}$, $I = 6.0 \, \text{A}$, and $r = 0.1 \, \text{m}$. Substituting these values, we get $B = \frac{4\pi \times 10^{-7} \times 6.0}{2 \times 0.1} = 3.8 \times 10^{-5} \, \text{T}$.

A Circular Loop of Wire of Radius 10 Cm Carries