Two coaxial circular coils of radius R = 15 cm,each carrying 4.0 A in the same direction,are positioned a distance d = 20 cm apart,as shown in the figure.Calculate the magnitude of the magnetic field halfway between the coils along the line connecting their centers.

Question

Quizplus · Accepted Answer

The magnetic field at a point halfway between the two coaxial circular coils can be found using the formula:

B = μ0 * I * (N1 * N2) / 2 * d

where B is the magnetic field, μ0 is the permeability of free space (4π * 10^-7 T⋅m/A), I is the current in each coil (4.0 A), N1 and N2 are the number of turns in each coil (assumed to be 1 in this problem), and d is the distance between the coils (20 cm).

Plugging in the given values, we get:

B = (4π * 10^-7 T⋅m/A) * 4.0 A * (1 * 1) / 2 * 0.20 m
B = 1.9 × 10^-5 T

Therefore, the answer is C: 1.9 × 10^-5 T.

Two Coaxial Circular Coils of Radius R = 15 Cm,each