The coil in a 60-Hz ac generator has 125 turns,each having an area of 3.0 × 10^-2 m² and is rotated in a uniform 0.12-T magnetic field.What is the peak output voltage of this generator? A) 170 V B) 120 V C) 200 V D) 110 V E) 220 V

Question

Quizplus · Accepted Answer

The peak output voltage (emf) of an AC generator is given by the formula: E_peak = NABω, where N is the number of turns, A is the area of each turn, B is the magnetic field strength, and ω is the angular velocity in radians per second. First, convert the frequency to angular velocity: ω = 2πf = 2π(60 Hz). Then, calculate E_peak = 125 turns × 3.0 × 10^-2 m² × 0.12 T × 2π(60 Hz) ≈ 170 V.

The Coil in a 60-Hz Ac Generator Has 125 Turns,each