A 120-V rms voltage at 60.0 Hz is applied across an inductor,a capacitor,and a resistor in series.If the peak current in this circuit is 0.8484 A,what is the impedance of this circuit?
A) 200 Ω
B) 141 Ω
C) 20.4 Ω
D) 120 Ω
E) 100 Ω

Question

Quizplus · Accepted Answer

The impedance of a series circuit is given by the formula Z = sqrt(R^2 + (XL - XC)^2), where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance. In this problem, we are given the peak current and the voltage, so we can use Ohm's law to find the impedance: Z = V/I = 120 V / 0.8484 A = 141 Ω.

A 120-V Rms Voltage at 60