If a beam of electromagnetic radiation has an intensity of 120 W/m²,what is the maximum value of the electric field? (c = 3.0 × 10⁸ m/s,μ₀ = 4π × 10^-7 T • m/A, A) 1.5 kV/m B) 1.0 µT C) 1.0 µV/m D) 0.30 kV/m E) 0.0032 V/m

Question

Quizplus · Accepted Answer

The intensity I of electromagnetic radiation is related to the amplitude E of the electric field by the equation:
I = cε0E2/2
where ε0 is the electric constant.
Solving for E yields:
E = sqrt(2I/(cε0))
Plugging in the given values, we get:
E = sqrt(2 x 120/(3x10^8 x 8.85x10^-12)) = 0.304 kV/m
Therefore, the maximum value of the electric field is 0.304 kV/m, which corresponds to choice D.

If a Beam of Electromagnetic Radiation Has an Intensity of 120