An 800-kHz radio signal is detected at a point 8.5 km distant from a transmitter tower.The electric field amplitude of the signal at that point is 0.90 V/m.Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed.What is the average electromagnetic energy density at that point? ,μ0 = 4π × 10-7 T • m/A,
A) 3.6 pJ/m3
B) 5.1 pJ/m3
C) 7.2 pJ/m3
D) 10 pJ/m3
E) 14 pJ/m3
Correct Answer:
Verified
Q16: The magnitude of the electric field at
Q17: When an electromagnetic wave falls on a
Q18: The y-component of the electric field of
Q19: Given that the wavelengths of visible light
Q20: A planar electromagnetic wave is propagating in
Q22: A radiometer has two square vanes (each
Q23: A sinusoidal electromagnetic wave in vacuum delivers
Q24: A very small source of light that
Q25: An electromagnetic wave has a peak electric
Q26: An 800-kHz radio signal is detected at
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents