A proton in a certain particle accelerator has a kinetic energy that is equal to its rest energy.What is the TOTAL energy of the proton as measured by a physicist working with the accelerator? (c = 3.00 × 10⁸ m/s,m_proton = 1.67 × 10^-27 kg)

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Quizplus · Accepted Answer

The total energy of a particle is given by the equation E = sqrt((pc)^2 + (mc^2)^2), where p is the momentum of the particle, m is the mass of the particle, and c is the speed of light. In this case, the kinetic energy of the proton is equal to its rest energy, so we have:1/2 mv^2 = mc^2Solving for v, we get:v = cSubstituting this into the equation for total energy, we get:E = sqrt((pc)^2 + (mc^2)^2)= sqrt((mc)^2 + (mc^2)^2)= sqrt(2) mc^2= 2.07 × 10^-10 J

A Proton in a Certain Particle Accelerator Has a Kinetic