Upon being struck by 240-nm photons,a metal ejects electrons with a maximum kinetic energy of What is the work function of this metal? (h = 6.626 × 10^-34 J • s, ,1 eV = 1.60 × 10^-19 J) A) 3.73 eV B) 3.13 eV C) 4.33 eV D) 4.92 eV

Question

Quizplus · Accepted Answer

The work function (Φ) can be calculated using the following formula:

Φ = hf - KE_max

Where h is Planck's constant and f is the frequency of the incident light.

We are given the wavelength of the incident light (240 nm), which can be used to find its frequency:

c = λf

where c is the speed of light, λ is the wavelength, and f is the frequency.

Plugging in the values:

f = c/λ = (3.00 × 10^8 m/s)/(240 × 10^-9 m) = 1.25 × 10^15 Hz

Now we can calculate the work function:

Φ = hf - KE_max
   = (6.626 × 10^-34 J·s) × (1.25 × 10^15 Hz) - (11.83 eV × 1.60 × 10^-19 J/eV)
   = 3.73 eV

Therefore, the best choice is A.

Upon Being Struck by 240-Nm Photons,a Metal Ejects Electrons with a Maximum