Light of wavelength 105 nm falls on a metal surface for which the work function is 5.00 eV.What is the minimum de Broglie wavelength of the photoelectrons emitted from this metal? (h = 6.626 × 10-34 J • s = 4.14 × 10-15 eV • s,c = 3.00 × 108 m/s,
, 
A) 0.24 nm
B) 0.33 nm
C) 0.47 nm
D) 0.66 nm
E) 0.94 nm
Correct Answer:
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