The Fermi energy of rubidium at a temperature of 5 K is 1.85 eV.An electron state in rubidium is 0.007 eV above the Fermi level.What is the probability that this state is occupied at a temperature of 9K? (m_el = 9.11 × 10^-31 kg,h = 6.626 × 10^-34 J • s,Boltzmann constant = A) 1 × 10^-4 B) 2 × 10^-5 C) 5 × 10^-6 D) 1 × 10^-6 E) 2 × 10^-7

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The Answer of The Fermi energy of rubidium at a temperature of 5 K is 1.85 eV.An electron state in rubidium is 0.007 eV above the Fermi level.What is the probability that this state is occupied at a temperature of 9K? (m_el = 9.11 × 10^-31 kg,h = 6.626 × 10^-34 J • s,Boltzmann constant = A) 1 × 10^-4 B) 2 × 10^-5 C) 5 × 10^-6 D) 1 × 10^-6 E) 2 × 10^-7

The Fermi Energy of Rubidium at a Temperature of 5