A 1000 kg car experiences a net force of 9500 N while decelerating from 30.0 m/s to 23.4 m/s. How far does it travel while slowing down?
A) 18.5 m
B) 17.4 m
C) 20.2 m
D) 21.9 m

Question

Quizplus · Accepted Answer

Using the work-energy principle, the work done by the net force is equal to the change in kinetic energy. The initial kinetic energy is (1/2) * 1000 * (30)^2 and the final kinetic energy is (1/2) * 1000 * (23.4)^2. The work done is force times distance, so 9500 * d = change in kinetic energy. Solving for d gives approximately 18.5 m.

A 1000 Kg Car Experiences a Net Force of 9500