Object A has a position as a function of time given by _A(t) = (3.00 m/s) t
+ (1.00 m/s²) t²

Object B has a position as a function of time given by
_B(t) = (4.00 m/s) t
+ (-1.00 m/s²) t²

All quantities are SI units.What is the distance between object A and object B at time t = 3.00 s?

Question

Object A has a position as a function of time given by

_A(t) = (3.00 m/s) t

+ (1.00 m/s²) t²

Object B has a position as a function of time given by

_B(t) = (4.00 m/s) t

+ (-1.00 m/s²) t²

All quantities are SI units.What is the distance between object A and object B at time t = 3.00 s?

Quizplus · Accepted Answer

The distance between object A and B at time t is given by: d(t) = |_A(t) - _B(t)| Plugging in t = 3.00 s and simplifying, we get: d(3.00 s) = |(3.00 m/s)(3.00 s) - (4.00 m/s)(3.00 s)| d(3.00 s) = |-3.00 m| d(3.00 s) = 3.00 m Therefore, the distance between object A and B at time t = 3.00 s is 3.00 m, which corresponds to choice C.

Object a Has a Position as a Function of Time