As shown in the figure,a container has a vertical tube,whose inner radius is 32.00 mm,connected to it at its side.An unknown liquid reaches level A in the container and level B in the tube-level A being 5.0 cm higher than level B.The liquid supports a 20.0-cm high column of oil,between levels B and C,whose density is 460 kg/m³.What is the density of the unknown liquid? A) 1800 kg/m³ B) 2000 kg/m³ C) 1400 kg/m³ D) 1600 kg/m³ E) 1700 kg/m³

Question

Quizplus · Accepted Answer

From the figure, we can see that the pressure at point A and point B are the same. Therefore, we have:
P_A = P_B
ρ_unknown*g*h_A = ρ_oil*g*h_BC + ρ_unknown*g*h_B
where g is the acceleration due to gravity, h_A = 0.05 m, h_B = length of tube (unknown), and h_BC = 0.2 m.
Rearranging the equation, we get:
ρ_unknown = ρ_oil*(h_BC/(h_A - h_B)) = 1800 kg/m^3.
Therefore, the answer is (A) 1800 kg/m^3.

As Shown in the Figure,a Container Has a Vertical Tube,whose