An electric dipole is made of two charges of equal magnitudes and opposite signs.The positive charge,q = 1.0 μC,is located at the point (x,y,z) = (0.00 cm,1.0 cm,0.00 cm) ,while the negative charge is located at the point (x,y,z) = (0.00 cm,-1.0 cm,0.00 cm) .How much work will be done by an electric field
= (3.0 × 106 N/C) 
To bring the dipole to its stable equilibrium position?
A) 0.060 J
B) 0.030 J
C) 0.00 J
D) 0.020 J
E) 0.12 J
Correct Answer:
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