A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA.How many electrons per second pass a given cross section of the wire? (e = 1.60 × 10^-19C)

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The current (I) is 260 mA or 0.26 A. The charge of one electron (e) is 1.60 × 10^-19 C. The number of electrons per second is given by I/e = 0.26 / (1.60 × 10^-19) = 1.625 × 10^18, which is approximately 1.6 × 10^18.

A Gold Wire That Is 1