Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV.What is the maximum kinetic energy of the photoelectrons emitted from the metal? (c = 3.00 × 10⁸ m/s,
H = 6.626 × 10^-34 J • s = 4.141 × 10^-15 ev • s,1 eV = 1.60 × 10^-19 J)

Question

Quizplus · Accepted Answer

The energy of the incident photon is calculated using E = hc/λ. Converting 400 nm to meters, we get 400 × 10^-9 m. Substituting the given values, E = (4.141 × 10^-15 eV • s × 3.00 × 10^8 m/s) / (400 × 10^-9 m) = 3.11 eV. The maximum kinetic energy of the photoelectrons is the photon energy minus the work function: 3.11 eV - 1.70 eV = 1.41 eV.

Light of Wavelength 400 Nm Falls on a Metal Surface