A dragster starts from rest and travels 1/4 mi in 6.70 s with constant acceleration.What is its velocity when it crosses the finish line?
A) 296 mi/h
B) 269 mi/h
C) 188 mi/h
D) 135 mi/h

Question

Quizplus · Accepted Answer

Firstly, we need to determine the acceleration of the dragster, which can be found using the equation:

d = 0.5at^2

Where d is the distance traveled (1/4 mi = 402.336 m), t is the time taken (6.70 s) and a is the acceleration. Rearranging the equation, we get:

a = 2d/t^2

a = 2(402.336)/(6.70^2)

a = 10.952 m/s^2

Now, using the equation for velocity:

v = u + at

Where u is the initial velocity (0 m/s) and t is the time taken (6.70s), we get:

v = 0 + (10.952 x 6.70)

v = 73.42 m/s

Converting to mph:

v = 73.42 x 2.23694

v = 164.12 mph

Therefore, the velocity when it crosses the finish line is approximately 164 mph. The only answer choice that is close to this is Option B, which is 269 mph.

A Dragster Starts from Rest and Travels 1/4 Mi in 6.70