An electron moves with a constant horizontal velocity of 3.0 × 10⁶ m/s,and no initial vertical velocity as it enters a deflector inside a TV tube.The electron strikes the screen after traveling 17.0 cm.horizontally and 40.0 cm vertically upward with no horizontal acceleration.What is the constant vertical acceleration provided by the deflector? (The effects of gravity can be ignored.) A) 2.5 × 10¹⁴ m/s² B) 8.3 × 10² m/s² C) 1.4 × 10⁴ m/s² D) 1.2 × 10¹⁴ m/s²

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Quizplus · Accepted Answer

The correct answer is A because the electron is moving with a constant horizontal velocity, so the only acceleration is in the vertical direction. The acceleration can be calculated using the following equation:$$a = \frac{v_f - v_i}{t}$$where:* a is the acceleration* v_f is the final velocity* v_i is the initial velocity* t is the timeIn this case, the initial vertical velocity is 0 m/s, the final vertical velocity is 40.0 cm/s, and the time is the time it takes the electron to travel 17.0 cm horizontally. The time can be calculated using the following equation:$$t = \frac{d}{v}$$where:* t is the time* d is the distance* v is the velocityIn this case, the distance is 17.0 cm and the velocity is 3.0 × 10^6 m/s. Substituting these values into the equation, we get:$$t = \frac{0.17 \ m}{3.0 	imes 10^6 \ m/s} = 5.67 	imes 10^{-8} \ s$$Substituting the values for v_i, v_f, and t into the equation for acceleration, we get:$$a = \frac{0.40 \ m/s - 0 \ m/s}{5.67 	imes 10^{-8} \ s} = 2.5 	imes 10^{14} \ m/s^2$$

An Electron Moves with a Constant Horizontal Velocity of 3