Two space stations are at rest relative to each other and are 6.0 × 10⁷ m apart,as measured by observers on the stations.A spaceship traveling from one station to the other at 0.90c relative to the stations passes both of them,one after the other.As measured by an observer in the spaceship,how long does it take to travel from one station to the other? (c = 3.00 × 10⁸ m/s) A)97 ms B)220 ms C)510 ms D)58 ms E)39 ms

Question

Quizplus · Accepted Answer

Explanation:The time it takes for the spaceship to travel from one station to the other, as measured by an observer in the spaceship, is given by:$$t = \frac{d}{v}$$where:* d is the distance between the two stations (6.0 × 10^7 m)* v is the speed of the spaceship relative to the stations (0.90c)Substituting these values into the equation, we get:$$t = \frac{6.0 	imes 10^7 	ext{ m}}{0.90 	imes 3.00 	imes 10^8 	ext{ m/s}} = 0.097 	ext{ s} = 97 	ext{ ms}$$Therefore, the correct answer is A) 97 ms.

Two Space Stations Are at Rest Relative to Each Other