An electron has a speed of 0.643c. Through what potential difference would the electron need to be accelerated (starting from rest) in order to reach this speed? (c = 3.00 × 10⁸ m/s, e = 1.60 × 10^-19 C,
M_el = 9.11 × 10^-31 kg)

Question

Quizplus · Accepted Answer

The kinetic energy of the electron can be calculated using the formula:
KE = (1/2) * m * v^2
where m is the mass of the electron and v is its velocity.

Substituting the given values, we get:
KE = (1/2) * (9.11 × 10^-31 kg) * (0.643c)^2
KE = 3.01 × 10^-14 J

The potential difference can be calculated using the formula:
Potential difference = KE / e
where e is the charge of the electron.

Substituting the given values, we get:
Potential difference = (3.01 × 10^-14 J) / (1.60 × 10^-19 C)
Potential difference = 188.2 × 10^3 V
Potential difference = 188.2 kV

Therefore, the closest answer is option A) 160 kV.

An Electron Has a Speed of 0