A 8.0-m long wire with a mass of 10 g is under tension.A transverse wave for which the frequency is 570 Hz,the wavelength is 0.10 m,and the amplitude is 3.7 mm is propagating on the wire.The maximum transverse acceleration of a point on a wire is closest to A)47,000 m/s². B)41,000 m/s². C)35,000 m/s². D)29,000 m/s². E)53,000 m/s².

Question

Quizplus · Accepted Answer

The maximum transverse acceleration $a_{max}$ of a point on the wire can be calculated using the formula $a_{max} = (2\pi f)^2 \cdot A$, where $f$ is the frequency and $A$ is the amplitude. Given $f = 570$ Hz and $A = 3.7$ mm $= 0.0037$ m, $a_{max} = (2\pi \cdot 570)^2 \cdot 0.0037 \approx 47,000$ m/s$^2$.

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