Motor oil,with a viscosity of 0.250 N • s/m²,is flowing through a tube that has a radius of 5.00 mm and is 25.0 cm long.The drop in pressure is 300 kPa.What is the volume of oil flowing through the tube per second?

Question

Quizplus · Accepted Answer

We can use Poiseuille's Law which gives the volume flow rate as: Q = πr^4ΔP/8ηL where r is the radius of the tube, ΔP is the drop in pressure, η is the viscosity of the oil and L is the length of the tube. Substituting the given values, we get: Q = π(5.00×10^-3 m)^4×(300×10^3 Pa)/(8×0.250 N·s/m^2×25.0×10^-2 m) Q = 1.18×10^-3 m^3/s = 0.00118 m^3/s Therefore, the volume of oil flowing through the tube per second is 0.00118 m^3/s or 0.00118 m³/s (in scientific notation). The best choice is C.

Motor Oil,with a Viscosity of 0