A very large sheet of a conductor carries a uniform charge density of 4.00 pC/mm² on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor? (ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A) 4.52 × 10⁵ N/C B) 2.26 × 10⁵ N/C C) 9.04 × 10⁵ N/C D) 0.452 N/C E) 0.226 N/C

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Quizplus · Accepted Answer

The electric field strength outside a charged conductor is given by E = σ/2ε0, where σ is the surface charge density and ε0 is the permittivity of free space. Plugging in the given values, we get E = (4.00 pC/mm^2) / (2 * 8.85 × 10^-12 C^2/N ∙ m^2) = 4.52 × 10^5 N/C.

A Very Large Sheet of a Conductor Carries a Uniform