A parallel-plate capacitor with plate separation of 1.0 cm has square plates,each with an area of 6.0 × 10^-2 m².What is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.4 is placed between the plates,completely filling them? (ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)15 × 10^-12 F B)15 × 10^-14 F C)64 × 10^-14 F D)1.3 × 10^-12 F E)1.3 × 10^-10 F

Question

Quizplus · Accepted Answer

The capacitance of a parallel-plate capacitor with a dielectric is given by C = κε₀A/d. Substituting the given values: C = (2.4)(8.85 × 10⁻¹² C²/N∙m²)(6.0 × 10⁻² m²)/(0.01 m) = 1.3 × 10⁻¹⁰ F.

A Parallel-Plate Capacitor with Plate Separation of 1